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10v^2+25v-60=0
a = 10; b = 25; c = -60;
Δ = b2-4ac
Δ = 252-4·10·(-60)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3025}=55$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-55}{2*10}=\frac{-80}{20} =-4 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+55}{2*10}=\frac{30}{20} =1+1/2 $
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